leetcode: 74. Search a 2D Matrix

Q

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

Integers in each row are sorted from left to right.
The first integer of each row is greater than the last integer of the previous row.
For example,

Consider the following matrix:

[  [1,   3,  5,  7],  [10, 11, 16, 20],  [23, 30, 34, 50]]

Given target = 3, return true.

AC

class Solution(object):    def searchMatrix(self, matrix, target):        """        :type matrix: List[List[int]]        :type target: int        :rtype: bool        """        if not matrix:            return False        m, n = len(matrix), len(matrix[0])        left, right = 0, m * n        while left < right:            mid = left + (right - left) / 2            if matrix[mid / n][mid % n] >= target:                right = mid            else:                left = mid + 1        return left < m * n and matrix[left / n][left % n] == targetif __name__ == "__main__":    matrix = [[1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50]]    assert Solution().searchMatrix(matrix, 3) == True

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