leetcode 136-Single Number
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难度：easy
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
2. 将list里面的每个element变成dictionary里的key，element在list里面出现的次数则为value，最后找到value=1时对应的key即可。
3. dictionary操作：
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