函数判断year是不是润年

#include<stdio.h>#include<stdlib.h>int leap_year(int year){    return (((year%4==0) && (year%100!=0)) ||( year%400 ==0));}int main(){    int re = 0;    int year = 0;    printf("请输入年份:");    scanf("%d",&year);    re = leap_year(year);    if(re)    {        printf("是润年");    }    else    {        printf("不是润年");    }    system("pause");    return 0;}