函数判断year是不是润年

#include<stdio.h>int leap(int *year){    int l=0;    if(((*year%4==0)&&(*year%100!=0))||(*year%400==0))        return 1;    else        return 0;}int main(){    int year=0;    int l=0;    printf("please enter the year>");    scanf("%d",&year);    l=leap(&year);    if(l==1)        printf("%d is leap year!\n",year);    else        printf("%d is not leap year!\n",year);    return 0;}