codevs1011数的计算

#include <iostream>using namespace std;int n,s=1;int count(int tt) 

{int i;if(tt/2==0) return 0;else{for(i=1;i<=tt/2;++i){++s;if(i>=2) count(i);else continue;}}}int main()

{

cin>>n;count(n);cout<<s;

return 0;

}