算法系列(11)LeetCode136 Single Number
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Given an array of integers, every element appears twice except for one. Find that single one.
决定以后刷题一定要记下来整个思路,方便以后看
思路:采用异或运算,如果是相同的两个数进行异或就又变成0了,那么最后不是0那个一定就是要找的那个咯
/** * @param {number[]} nums * @return {number} */var singleNumber = function(nums) { var a = 0; for(var i=0; i<nums.length; i++){ a=a^nums[i]; } return a;};
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