javaSpring使用maven初始搭建步骤java项目

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1、在maven项目中修改pom.xml引入关于spring的依赖。

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">  <modelVersion>4.0.0</modelVersion>  <groupId>com.iflytek</groupId>  <artifactId>firstSpring</artifactId>  <version>0.0.1-SNAPSHOT</version>    <dependencies>   <dependency>        <groupId>org.springframework</groupId>        <artifactId>spring-core</artifactId>        <version>4.3.13.RELEASE</version>        <!--  <exclusions>            <exclusion>                <groupId>commons-logging</groupId>                <artifactId>commons-logging</artifactId>            </exclusion>        </exclusions>  -->    </dependency>  <dependency>        <groupId>org.springframework</groupId>        <artifactId>spring-context</artifactId>        <version>4.3.13.RELEASE</version>        <scope>runtime</scope>   </dependency>   <dependency>        <groupId>log4j</groupId>        <artifactId>log4j</artifactId>        <version>1.2.17</version>    </dependency>  </dependencies></project>

2、加入必须的配置文件applicationContext.xml文件

<?xml version="1.0" encoding="UTF-8"?><beans xmlns="http://www.springframework.org/schema/beans"    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"    xsi:schemaLocation="http://www.springframework.org/schema/beans        http://www.springframework.org/schema/beans/spring-beans.xsd"><!--     <bean id="..." class="...">        collaborators and configuration for this bean go here    </bean>    <bean id="..." class="...">        collaborators and configuration for this bean go here    </bean> -->    <!-- more bean definitions go here     UserDao ud = new UserDao();    --><bean id="ud" class="com.iflytek.dao.UserDao"></bean><bean id="us" class="com.iflytek.service.UserService"><property name="userDao" ref="ud"></property></bean></beans>

通过引入bean的方式，创建和初始化需要的对象

3、加载其他需要的配置文件和依赖（如log4j.property和hibernate的dependency）
4、写java代码进行测试

譬如以上配置的两个bean中，分别配置了Userservice的对象us和UserDao的对象ud，在测试类中，只要UserService service = context.getBean("us", UserService.class);即可一获得已经定义的UserService对象，在service中存在userDao的属性，通过service对象调用getter方法获得dao对象（因为到时私有的，所以要get特然获得），即可使用dao类中的方法。

附简单的测试代码

User类

package com.iflytek.domain;public class User {private int id;private String name;public int getId() {return id;}public void setId(int id) {this.id = id;}public String getName() {return name;}public void setName(String name) {this.name = name;}@Overridepublic String toString() {return "User [id=" + id + ", name=" + name + "]";}}

UserService类

package com.iflytek.service;import com.iflytek.dao.UserDao;public class UserService {private UserDao userDao1;public UserDao getUserDao() {return userDao1;}public void setUserDao(UserDao userDao1) {this.userDao1 = userDao1;}}

UserDao类

package com.iflytek.dao;import com.iflytek.domain.User;public class UserDao {public User getUserById(int i) {User user = new User();user.setId(10);user.setName("zhangsan");return user;}}

测试类App.class

package com.iflytek.test;import org.springframework.context.ApplicationContext;import org.springframework.context.support.ClassPathXmlApplicationContext;import com.iflytek.domain.User;import com.iflytek.service.UserService;public class App {public static void main(String[] args) {ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");//把IOC容器中的us对象取出来UserService service = context.getBean("us", UserService.class);User user = service.getUserDao().getUserById(10);System.out.println(user.getName());}}

初学者，大家一起交流，不喜勿喷。

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