条件·复数四则运算
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/*头一次写一百五十行的代码。也算是迄今写过最长的代码,虽然问题很简单,但是我还是选择暴力。*/
7-3 复数四则运算(10 分)
本题要求编写程序,计算2个复数的和、差、积、商。
输入格式:
输入在一行中按照a1 b1 a2 b2
的格式给出2个复数C1=a1+b1i
和C2=a2+b2i
的实部和虚部。题目保证C2不为0。
输出格式:
分别在4行中按照(a1+b1i) 运算符 (a2+b2i) = 结果
的格式顺序输出2个复数的和、差、积、商,数字精确到小数点后1位。如果结果的实部或者虚部为0,则不输出。如果结果为0,则输出0.0。
输入样例1:
2 3.08 -2.04 5.06
输出样例1:
(2.0+3.1i) + (-2.0+5.1i) = 8.1i(2.0+3.1i) - (-2.0+5.1i) = 4.0-2.0i(2.0+3.1i) * (-2.0+5.1i) = -19.7+3.8i(2.0+3.1i) / (-2.0+5.1i) = 0.4-0.6i
输入样例2:
1 1 -1 -1.01
输出样例2:
(1.0+1.0i) + (-1.0-1.0i) = 0.0(1.0+1.0i) - (-1.0-1.0i) = 2.0+2.0i(1.0+1.0i) * (-1.0-1.0i) = -2.0i(1.0+1.0i) / (-1.0-1.0i) = -1.0
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
double a1,b1,a2,b2;
scanf("%lf %lf %lf %lf",&a1,&b1,&a2,&b2);
if(b1<0&&b2<0)///其实核心还是中间,但是正负号的问题就这样暴力破解
{
if(b1+b2<0.09) printf("(%.1f%.1fi) + (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1+a2);
else if(a1+a2<0.09) printf("(%.1f%.1fi) + (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,b1+b2);
else
{
if(b1+b2<0) printf("(%.1f%.1fi) + (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
else printf("(%.1f+%.1fi) + (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
}
if(fabs(b1-b2)<0.09) printf("(%.1f%.1fi) - (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1-a2);
else if(fabs(a1-a2)<0.09) printf("(%.1f%.1fi) - (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,b1-b2);
else
{
if(b1-b2<0) printf("(%.1f%.1fi) - (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
else printf("(%.1f%.1fi) - (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
}
if(a1==0&&b1==0) printf("(%.1f%.1fi) * (%.1f%.1fi) = 0.0\n",a1,b1,a2,b2);
else if((a1*a2-b1*b2)<0.09) printf("(%.1f%.1fi) * (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,a1*b2+a2*b1);
else if((a1*b2+a2*b1)<0.09) printf("(%.1f%.1fi) * (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1*a2-b1*b2);
else
{
if(a1*b2+a2*b1<0) printf("(%.1f%.1fi) * (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
else printf("(%.1f%.1fi) * (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
}
if(a1==0&&b1==0) printf("(%.1f%.1fi) / (%.1f%.1fi) = 0.0\n",a1,b1,a2,b2);
else if(fabs((a1*a2+b1*b2)/(a2*a2+b2*b2))<0.09) printf("(%.1f%.1fi) / (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else if(fabs((-a1*b2+a2*b1)/(a2*a2+b2*b2))<0.09) printf("(%.1f%.1fi) / (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2));
else
{
if((-a1*b2+a2*b1)/(a2*a2+b2*b2)<0) printf("(%.1f%.1fi) / (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else printf("(%.1f%.1fi) / (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
}
}///后面都是一样的,就是负数前面的加号删掉了
else if(b1<0&&b2>0)
{
if(b1+b2<0.09) printf("(%.1f%.1fi) + (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1+a2);
else if(a1+a2<0.09) printf("(%.1f%.1fi) + (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,b1+b2);
else
{
if(b1+b2<0) printf("(%.1f%.1fi) + (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
else printf("(%.1f%.1fi) + (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
}
if(fabs(b1-b2)<0.09) printf("(%.1f%.1fi) - (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1-a2);
else if(fabs(a1-a2)<0.09) printf("(%.1f%.1fi) - (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,b1-b2);
else
{
if(b1-b2<0) printf("(%.1f%.1fi) - (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
else printf("(%.1f%.1fi) - (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
}
if(a1==0&&b1==0) printf("(%.1f%.1fi) * (%.1f+%.1fi) = 0.0\n",a1,b1,a2,b2);
else if((a1*a2-b1*b2)<0.09) printf("(%.1f%.1fi) * (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,a1*b2+a2*b1);
else if((a1*b2+a2*b1)<0.09) printf("(%.1f%.1fi) * (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1*a2-b1*b2);
else
{
if(a1*b2+a2*b1<0) printf("(%.1f%.1fi) * (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
else printf("(%.1f%.1fi) * (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
}
if(a1==0&&b1==0) printf("(%.1f%.1fi) / (%.1f+%.1fi) = 0.0\n",a1,b1,a2,b2);
else if(fabs((a1*a2+b1*b2)/(a2*a2+b2*b2))<0.09) printf("(%.1f%.1fi) / (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else if(fabs((-a1*b2+a2*b1)/(a2*a2+b2*b2))<0.09) printf("(%.1f%.1fi) / (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2));
else
{
if((-a1*b2+a2*b1)/(a2*a2+b2*b2)<0) printf("(%.1f%.1fi) / (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else printf("(%.1f%.1fi) / (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
}
}
else if(b1>0&&b2<0)
{
if(b1+b2<0.09) printf("(%.1f+%.1fi) + (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1+a2);
else if(a1+a2<0.09) printf("(%.1f+%.1fi) + (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,b1+b2);
else
{
if(b1+b2<0) printf("(%.1f+%.1fi) + (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
else printf("(%.1f+%.1fi) + (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
}
if(fabs(b1-b2)<0.09) printf("(%.1f+%.1fi) - (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1-a2);
else if(fabs(a1-a2)<0.09) printf("(%.1f+%.1fi) - (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,b1-b2);
else
{
if(b1-b2<0) printf("(%.1f+%.1fi) - (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
else printf("(%.1f+%.1fi) - (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
}
if(a1==0&&b1==0) printf("(%.1f+%.1fi) * (%.1f%.1fi) = 0.0\n",a1,b1,a2,b2);
else if((a1*a2-b1*b2)<0.09) printf("(%.1f+%.1fi) * (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,a1*b2+a2*b1);
else if((a1*b2+a2*b1)<0.09) printf("(%.1f+%.1fi) * (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,a1*a2-b1*b2);
else
{
if(a1*b2+a2*b1<0) printf("(%.1f+%.1fi) * (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
else printf("(%.1f+%.1fi) * (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
}
if(a1==0&&b1==0) printf("(%.1f+%.1fi) / (%.1f%.1fi) = 0.0\n",a1,b1,a2,b2);
else if(fabs((a1*a2+b1*b2)/(a2*a2+b2*b2))<0.09) printf("(%.1f+%.1fi) / (%.1f%.1fi) = %.1fi\n",a1,b1,a2,b2,(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else if(fabs((-a1*b2+a2*b1)/(a2*a2+b2*b2))<0.09) printf("(%.1f+%.1fi) / (%.1f%.1fi) = %.1f\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2));
else
{
if((-a1*b2+a2*b1)/(a2*a2+b2*b2)<0) printf("(%.1f+%.1fi) / (%.1f%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else printf("(%.1f+%.1fi) / (%.1f%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
}
}
else///这才是最初的代码。Tab,一个写着小说,敲着代码的鬼畜文艺青年。。
{
if(b1+b2<0.09) printf("(%.1f+%.1fi) + (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1+a2);
else if(a1+a2<0.09) printf("(%.1f+%.1fi) + (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,b1+b2);
else
{
if(b1+b2<0) printf("(%.1f+%.1fi) + (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
else printf("(%.1f+%.1fi) + (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1+a2,b1+b2);
}
if(fabs(b1-b2)<0.09) printf("(%.1f+%.1fi) - (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1-a2);
else if(fabs(a1-a2)<0.09) printf("(%.1f+%.1fi) - (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,b1-b2);
else
{
if(b1-b2<0) printf("(%.1f+%.1fi) - (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
else printf("(%.1f+%.1fi) - (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1-a2,b1-b2);
}
if(a1==0&&b1==0) printf("(%.1f+%.1fi) * (%.1f+%.1fi) = 0.0\n",a1,b1,a2,b2);
else if(fabs(a1*a2-b1*b2)<0.09) printf("(%.1f+%.1fi) * (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,a1*b2+a2*b1);
else if(fabs(a1*b2+a2*b1)<0.09) printf("(%.1f+%.1fi) * (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,a1*a2-b1*b2);
else
{
if(a1*b2+a2*b1<0) printf("(%.1f+%.1fi) * (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
else printf("(%.1f+%.1fi) * (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,a1*a2-b1*b2,a1*b2+a2*b1);
}
if(a1==0&&b1==0) printf("(%.1f+%.1fi) / (%.1f+%.1fi) = 0.0\n",a1,b1,a2,b2);
else if(fabs((a1*a2+b1*b2)/(a2*a2+b2*b2))<0.09) printf("(%.1f+%.1fi) / (%.1f+%.1fi) = %.1fi\n",a1,b1,a2,b2,(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else if(fabs((-a1*b2+a2*b1)/(a2*a2+b2*b2))<0.09) printf("(%.1f+%.1fi) / (%.1f+%.1fi) = %.1f\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2));
else
{
if((-a1*b2+a2*b1)/(a2*a2+b2*b2)<0) printf("(%.1f+%.1fi) / (%.1f+%.1fi) = %.1f%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
else printf("(%.1f+%.1fi) / (%.1f+%.1fi) = %.1f+%.1fi\n",a1,b1,a2,b2,(a1*a2+b1*b2)/(a2*a2+b2*b2),(-a1*b2+a2*b1)/(a2*a2+b2*b2));
}
}
return 0;
}
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