hdoj 1039 Easier Done Than Said?（水题）

思路：规则翻译就好

代码如下：

#include <stdio.h>#include <stdlib.h>#include <string.h>/* run this program using the console pauser or add your own getch, system("pause") or input loop */#define  p 3.1415927int judge(char c){if(c=='a'||c=='e'||c=='i'||c=='o'||c=='u')return 1;else if (c=='\0')return -1;else return 0;}int main(int argc, char *argv[]) {char a[30];int i;int len;int flag;int sum;for(i=0;i<30;i++)a[i]='\0';while(scanf("%s",a)){if(a[0]=='e'&&a[1]=='n'&&a[2]=='d')break;flag=1;len=strlen(a);sum=0;for(i=0;i<len;i++){sum+=judge(a[i]);}for(i=0;i<len;i++){if(sum==0){flag=0;break;}if(judge(a[i])==1 && judge(a[i+1])==1 &&judge(a[i+2])==1){flag=0;break;}if(judge(a[i])==0 && judge(a[i+1])==0 &&judge(a[i+2])==0){flag=0;break;}if(a[i]==a[i+1]){if(a[i]!='e'&& a[i]!='o'){flag=0;break;}}}if(flag)printf("<%s> is acceptable.\n",a); elseprintf("<%s> is not acceptable.\n",a);for(i=0;i<30;i++)a[i]='\0'; } return 0;}