ajax提交form表单

<button type="submit" class="am-btn am-btn-primary" onclick="submitForm('/goods/savaAdd')">保存</button>

function submitForm(url) {

    //获取当前的表单    var form = new FormData(this)    $.ajax({            type: "POST",            url: url,            async: true,

    //.serialize()序列化表单数据            data: $("#adgdform").serialize(),            success:                function (responseText) {                    $("#con").html(responseText)                }            , error: function () {                alert("跳转失败");            }        }    )}