hdu 1041 计算机二进制n步操作（大数加法）

#include<iostream>
//#include<math.h>
using namespace std;
int a[1002][505];
int main()
{
    int i,n,j,t;
   
//    memset(a,0,sizeof(a));

   
    a[1][0]=0;a[2][0]=1;a[3][0]=1;


    for(i=4;i<=1000;i++)
    {
         t=0;
        for(j=0;j<=350;j++)
        {
                a[i][j]=a[i-1][j]+2*a[i-2][j]+t;
                t=a[i][j]/10;
                a[i][j]=a[i][j]%10;
               

        }
       
   
    }
   
    while(    cin>>n)
    {
        if(n==1)
        {
            cout<<"0"<<endl;
            continue;
        }
   
            int flag=0;
            for(i=350;i>=0;i--)
            {
                if(a[n][i]!=0||flag)
                {
                    cout<<a[n][i];
                    flag=1;
                }
            }

       
       
        cout<<endl;
   
    }
    return 0;
}