n*n个数按口字顺序存放

include <stdio.h>void main(){int a[10][10];int i,j,k,n,b=0;scanf("%d",&n);for ( i=0; i<n/2; i++){for ( j=i; j<n-i; j++) /*四个循环按不同的方向进行*/a[i][j] = ++b;for ( k=i+1,j--; k<n-i; k++ )a[k][j] = ++b;for ( j=--k,j--; j>=i; j-- )a[k][j] = ++b;for ( k--; k>i; k-- )a[k][i] = ++b;}if ( n%2 ) /*如果是单数的话，要加上最大的那个数放在中间*/a[i][i] = ++b;for ( i=0; i<n; i++){for ( j=0; j<n; j++)printf("%3d",a[i][j]);printf("/n");}}