pku 3264 Balanced Lineup线段树

第一次在pku做题，囧死了，这么一道题调了我N久

不过听说用RMQ-ST算法更高效，我用线段树做居然是4047ms

有点让我惊讶，居然可以慢成这样~~~~~~~~~

 

#include<stdio.h>#define N 50005struct node{ int l; int r; int min; int max;};node tree[3*N];int arr[N];void buid_tree(int k,int left,int right){int mid;int L,R;tree[k].l = left; tree[k].r = right;if(right-left == 1){tree[k].min = tree[k].max = arr[left];return ;}L = 2*k; R = L+1;mid = (tree[k].l+tree[k].r)/2;buid_tree(L,left,mid);buid_tree(R,mid,right);tree[k].min = tree[L].min > tree[R].min? tree[R].min:tree[L].min;tree[k].max = tree[L].max > tree[R].max? tree[L].max:tree[R].max;return ;}int tree_search_min(int k,int left,int right){int mid;int L,R;int lm = 1000005,rm = 1000005;if(left <= tree[k].l && right >= tree[k].r){ return tree[k].min;}L = 2*k; R = L+1;mid = (tree[k].l+tree[k].r)/2;if(left < mid) lm = tree_search_min(L,left,right);if(right > mid) rm = tree_search_min(R,left,right);return lm < rm? lm:rm;}int tree_search_max(int k,int left,int right){int mid;int L,R;int lm = 0,rm = 0;if(left <= tree[k].l && right >= tree[k].r){ return tree[k].max;}L = 2*k; R = L+1;mid = (tree[k].l+tree[k].r)/2;if(left < mid) lm = tree_search_max(L,left,right);if(right > mid) rm = tree_search_max(R,left,right);return lm > rm? lm:rm;}int main(){int n,q;int i;int a,b;while(scanf("%d %d",&n,&q) == 2){ for(i = 1;i <= n;i++)scanf("%d",arr+i);buid_tree(1,1,n+1);for(i = 0;i < q;i++){ scanf("%d %d",&a,&b); printf("%d/n",tree_search_max(1,a,b+1)-tree_search_min(1,a,b+1));}}return 0;}