POJ 3510 string

题意: 对某些特定字符转换

思路:优先判断特殊字符的转换,最后判断相应字符是否输出.

注意:结束符 "EOF"可以出现在任意位置.

代码:

#include <cstdio>#include <cstring>#include <iostream>using namespace std;int main(void){char s[90];char tmp[] = "floyd";while(true){gets(s);int i,j,len = strlen(s),k=0;char str[90];bool flag = false;for(i=0; i<len; ++i){if(s[i] == 'E' && s[i+1] == 'O' && s[i+2] == 'F'){flag = true;break;}else if(s[i] == ' ')str[k++] = ' ';else if(s[i] == 'd' && s[i+1] == 'd'){str[k++] = 'p';i++;}else if(s[i] == 'e' && s[i+1] == 'i' && s[i-1] != 'c'){str[k++] = 'i';str[k++] = 'e';i++;}else if(s[i] == 'p' && s[i+1] == 'i' && s[i+2] == 'n' && s[i+3] == 'k'){for(j=0; j<5; ++j)str[k++] = tmp[j];i += 3;}else if(s[i] >='a' && s[i] <= 'z')str[k++] = s[i];}if(!flag){str[k] = '/0';printf("%s/n",str);strcpy(s,"");}if(flag){str[k] = '/0';printf("%s/n",str);strcpy(s,"");break;}}return 0;}