JavaScrit 判断两个时间相差的各个阶段

来源：互联网发布：网络相关知识编辑：程序博客网时间：2024/06/05 20:58

<script type="text/javascript">function dateDiff( str1, str2 ) { var diff = Date.parse( str2 ) - Date.parse( str1 ); return isNaN( diff ) ? NaN : {  diff : diff,  ms : Math.floor( diff % 1000 ),   s : Math.floor( diff / 1000 % 60 ),   m : Math.floor( diff / 60000 % 60 ),     h : Math.floor( diff / 3600000 % 24 ),      d : Math.floor( diff / 86400000 ) };  }   var obj = dateDiff(new Date(new Date("2011-03-04 12:23:00".replace("-","/")) ), new Date("2011-03-05 12:24:00".replace("-","/"))); alert( obj.ms +"毫秒" + obj.s + " 秒"  + obj.m + " 分" + obj.h + " 小时" + obj.d + " 天：" );</script>

这些代码只是把两个时间做出了比较，可以自己试试，然后找出规律，做出自己想要的结果。多多分享。

以下应该更贴切些：

function mydiff(date1,date2,interval) { var second=1000, minute=second*60, hour=minute*60, day=hour*24, week=day*7;  date1 = new Date(date1); date2 = new Date(date2); var  timediff = date2 - date1;  if (isNaN(timediff)) return NaN; switch (interval)  { case "years": return date2.getFullYear() - date1.getFullYear();  case "months": return ( ( date2.getFullYear() * 12 + date2.getMonth() ) - ( date1.getFullYear() * 12 + date1.getMonth() ) );   case "weeks" : return Math.floor(timediff / week);    case "days" :  return Math.floor(timediff / day);    case "hours" : return Math.floor(timediff / hour);     case "minutes": return Math.floor(timediff / minute);     case "seconds": return Math.floor(timediff / second);     default: return undefined;     }  }   var o = mydiff(new Date(new Date("2011-03-04 12:23:00".replace("-","/")) ), new Date("2011-03-05 12:24:00".replace("-","/")),"days");   alert(o);