poj 1087 最大流

来源:互联网 发布:linux easybcd 编辑:程序博客网 时间:2024/05/20 06:41
#include <cstdio>#include <iostream>#include<queue>#include<set>#include<ctime>#include<algorithm>#include<cmath>#include<vector>#include<map>#include<cstring>using namespace std;const int inf=1<<30;const int maxn=1019;struct edge  {       int v, next;       int val;   } net[ 500100 ];   int n,num;char read[109][30];int level[maxn], Qu[maxn], out[maxn],next[maxn];  class Dinic {   public:       int end;      Dinic() {           end = 0;           memset( next, -1, sizeof(next) );       }       inline void insert( int x, int y, int c) {           net[end].v = y, net[end].val = c,          net[end].next = next[x],           next[x] = end ++;           net[end].v = x, net[end].val = 0,          net[end].next = next[y],           next[y] = end ++;       }       bool BFS( int S, int E ) {           memset( level, -1, sizeof(level) );           int low = 0, high = 1;           Qu[0] = S, level[S] = 0;           for( ; low < high; ) {               int x = Qu[low];               for( int i = next[x]; i != -1; i = net[i].next ) {                   if( net[i].val == 0 ) continue;                   int y = net[i].v;                   if( level[y] == -1 ) {                       level[y] = level[x] + 1;                       Qu[ high ++] = y;                   }               }               low ++;           }           return level[E] != -1;       }            int MaxFlow( int S, int E ){           int maxflow = 0;           for( ; BFS(S, E) ; ) {               memcpy( out, next, sizeof(out) );               int now = -1;               for( ;; ) {                   if( now < 0 ) {                       int cur = out[S];                       for(; cur != -1 ; cur = net[cur].next )                            if( net[cur].val && out[net[cur].v] != -1 && level[net[cur].v] == 1 )                               break;                       if( cur >= 0 ) Qu[ ++now ] = cur, out[S] = net[cur].next;                       else break;                   }                   int u = net[ Qu[now] ].v;                   if( u == E ) {                       int flow = inf;                       int index = -1;                       for( int i = 0; i <= now; i ++ ) {                           if( flow > net[ Qu[i] ].val )                               flow = net[ Qu[i] ].val, index = i;                       }                       maxflow += flow;                       for( int i = 0; i <= now; i ++ )                           net[Qu[i]].val -= flow, net[Qu[i]^1].val += flow;                       for( int i = 0; i <= now; i ++ ) {                           if( net[ Qu[i] ].val == 0 ) {                               now = index - 1;                               break;                           }                       }                   }                   else{                       int cur = out[u];                       for(; cur != -1; cur = net[cur].next )                            if (net[cur].val && out[net[cur].v] != -1 && level[u] + 1 == level[net[cur].v])                               break;                       if( cur != -1 )                           Qu[++ now] = cur, out[u] = net[cur].next;                       else out[u] = -1, now --;                   }               }           }           return maxflow;       }   };   int check(char *a){for(int i=0;i<num;i++)if(strcmp(read[i],a)==0)return i;strcpy(read[num],a);return num++;}int main(){char c[30];int tmp;char s[30];while(scanf("%d",&n)!=EOF){Dinic my;num=0;for(int i=0;i<n;i++){scanf("%s",c);tmp=check(c);my.insert(tmp,1009,1);}scanf("%d",&tmp);int n=tmp;while(tmp--){scanf("%s%s",s,c);int k=check(c);my.insert(1010,k,1);}scanf("%d",&tmp);while(tmp--){scanf("%s%s",s,c);int k=check(c);int g=check(s);my.insert(g,k,inf);}printf("%d\n",n-my.MaxFlow(1010,1009));}}