C# 统计N个相同子字符串的个数及位置

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 using System.Text.RegularExpressions;       /// <summary>        /// 计算字符串中子串出现的次数        /// </summary>        /// <param name="str">字符串</param>        /// <param name="substring">子串</param>        /// <returns>出现的次数</returns>        public  static int SubstringCount(string str, string substring)        {            if (str.Contains(substring))            {                string strReplaced = str.Replace(substring, "");                return (str.Length - strReplaced.Length) / substring.Length;            }            return 0;        }                        // 调用例子,这里仅提供参考的思路                private void FindPosition()            {                     sTemp="aabbccdd\r\naa3323\r\naa325sdf\r\n233asdf554\r\n"; // 这里是原始字符串                    int iCount = SubstringCount(sTemp, "\r\n"); // 这里\r\n是分割符                    if (iCount > 3)                    {                        Regex reg = new Regex("\r\n");                        Match mat = reg.Match(sTemp);                        int iCountTemp = 0;                        while (mat.Success)                        {                            iCountTemp++;                            //MessageBox.Show(mat.Index.ToString());//位置                            if (iCountTemp > 20)                            {                                sTemp = sTemp.Substring(0, mat.Index);                                break;                            }                            mat = reg.Match(sTemp, mat.Index + mat.Length);                        }                    }            }