part 3 Cache Memory 5
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Fully associative
cache structure
detailed relationships on cache address structure.
Following is the different of direct map and 8-set associative
Memory size = 528KB = 219
Block size = 32Bytes = 25
Number of blocks in cache = Cache size/Block size = 64KB/32B = 214/25 = 211
Number of bits in Tag = Total bits - Index bits - Offset bits = 19-11-5 = 3
The Compare Bits are compared with the corresponding Tag Bits in the Cache Directory.
The Set Select Bits are used to select a particular Set in the Cache.
The Byte Select Bits are used to select a particular byte in the accessed block.Memory size = 528KB = 219
Block size = 32Bytes = 25
Number of sets in cache = Cache size/(Set size * Block size) = 64KB/(8 blocks * 32B) = 214/(23 * 25) = 28
Number of bits in Tag = Total bits - Index bits - Offset bits = 19-8-5 = 6
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