zoj 2781 Rounders

//这题的大意就是对输出的数字进行判断，对于每一位数字，凡是满5就进1！#include "iostream"#include "string"#include "cmath"using namespace std;int main(){int testcase, i, len, temp1, temp2, ans;string num;cin >> testcase;while (testcase--){cin >> num;ans = 0;len = num.length();for (i = len - 1; i > 0; i--){temp1 = num[i] - 48;temp2 = num[i-1] - 48;if (temp1 >= 5)temp2 += 1;num[i-1] = temp2 + 48;}ans = (num[0] - 48)* pow(double (10), len-1);cout << ans << endl;}}