POJ3077 Rounders
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Rounders
Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 7605 Accepted: 4931
Description
For a given number, if greater than ten, round it to the nearest ten, then (if that result is greater than 100) take the result and round it to the nearest hundred, then (if that result is greater than 1000) take that number and round it to the nearest thousand, and so on ...
Input
Input to this problem will begin with a line containing a single integer n indicating the number of integers to round. The next n lines each contain a single integer x (0 <= x <= 99999999).
Output
For each integer in the input, display the rounded integer on its own line.
Note: Round up on fives.
Note: Round up on fives.
Sample Input
91514459912345678444444451445446
Sample Output
20104510010000000500000002000500
Source
South Central USA 2006
#include <stdio.h>#include <string.h>char str[20];int main(){ int t, n, a, b, len, i, jin; scanf("%d", &t); while(t--){ scanf("%s", str); len = strlen(str); while(len > 1){ --len; if(str[len] >= '5'){ str[len] = '0'; ++str[len-1]; }else str[len] = '0'; } jin = 0; if(str[0] > '9') jin = 1, str[0] = '0'; if(jin) putchar('1'); puts(str); } return 0;}
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