POJ 1703 (并查集)

Find them, Catch them

Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 20136 Accepted: 5963

Description

The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang Dragon and Gang Snake. However, the police first needs to identify which gang a criminal belongs to. The present question is, given two criminals; do they belong to a same clan? You must give your judgment based on incomplete information. (Since the gangsters are always acting secretly.)

Assume N (N <= 10^5) criminals are currently in Tadu City, numbered from 1 to N. And of course, at least one of them belongs to Gang Dragon, and the same for Gang Snake. You will be given M (M <= 10^5) messages in sequence, which are in the following two kinds:

1. D [a] [b]
where [a] and [b] are the numbers of two criminals, and they belong to different gangs.

2. A [a] [b]
where [a] and [b] are the numbers of two criminals. This requires you to decide whether a and b belong to a same gang.

Input

The first line of the input contains a single integer T (1 <= T <= 20), the number of test cases. Then T cases follow. Each test case begins with a line with two integers N and M, followed by M lines each containing one message as described above.

Output

For each message "A [a] [b]" in each case, your program should give the judgment based on the information got before. The answers might be one of "In the same gang.", "In different gangs." and "Not sure yet."

简单的并查集应用。。。可我开始时想傻×了。。。。甚至想做两层并查集

实际上。。。开一个数组，存放某人的敌人就好

#include<stdio.h>#include<string.h>#define clear(a,b) memset(a,b,sizeof(a))#define maxn 200000int fa[maxn],enemy[maxn];int getfa(int a){  if (fa[a] == a) return a;    else fa[a] = getfa(fa[a]);  return fa[a];}int judge(int a,int b){  return getfa(a) == getfa(b);}void unite(int a,int b){  fa[getfa(b)] = getfa(a);}void work(){  int m,n,i,b,a;  char ch;  clear(enemy,0);  scanf("%d%d",&n,&m);  for(i = 1;i <= n;i++) fa[i] = i;  for(i = 1;i <= m;i++) {    getchar();    scanf("%c%d%d",&ch,&a,&b);    if (ch == 'D') {      if (enemy[a]) unite(enemy[a],b);      if (enemy[b]) unite(enemy[b],a);      enemy[a] = b;      enemy[b] = a;      }    else {      if (getfa(a) == getfa(enemy[b])) printf("In different gangs.\n");      else if (getfa(a) == getfa(b)) printf("In the same gang.\n");      else printf("Not sure yet.\n");      }  }   return ;}int main(){  int k;  scanf("%d",&k);  while (k--) work();  return 0;}