u Calculate e解题报告

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 16844    Accepted Submission(s): 7307

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e- -----------0 11 22 2.53 2.6666666674 2.708333333

 

Source

Greater New York 2000

 

Recommend

JGShining

 

#include<iostream>using namespace std;double pow(double i){double sum=1,j;for(j=1;j<=i;j++){sum*=j;}return 1/sum;}double he(double i){double sun=0,sum=0,j;for(j=1;j<=i;j++){sum+=pow(j);}return sum;}int main(){double a,i,j,sum=1,e;cout<<'n'<<' '<<'e'<<endl;cout<<'-'<<' '<<"-----------"<<endl;cout<<'0'<<' '<<'1'<<endl;cout<<'1'<<' '<<'2'<<endl;cout<<'2'<<' '<<"2.5"<<endl;for(i=3;i<=9;i++){cout<<i<<' ';e=he(i);printf("%.9f\n",e+1);}return 0;}