复数类中运算符重载（第八周任务一）

/* (程序头部注释开始)
* 程序的版权和版本声明部分
* Copyright (c) 2011, 烟台大学计算机学院学生 
* All rights reserved.
* 文件名称：                              
* 作    者： 李超                             
* 完成日期：    2012  年  4  月   9  日
* 版 本 号：          01.08.01


* 对任务及求解方法的描述部分
* 输入描述： 

* 问题描述：定义一个复数类重载运算符+、-、*、/，使之能用于复数的加减乘除。用类的友元函数，而不是成员函数，完成上面提及的运算符的重载

扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。设Complex c; double d; c?d和d?c的结果为将d视为实部为d的复数同c运算的结果（其中?为+、-、*、/之一）。 

* 程序输出： 
* 程序头部的注释结束

*/

头文件Complex.h

#include <iostream>using namespace std;class Complex{public:Complex ()  {real = 0; imag = 0;}Complex(double r, double i){real = r; imag = i;}friend Complex operator + (Complex &c1, Complex &c2);friend Complex operator + (Complex &c1, double c2);friend Complex operator + (double c1, Complex &c2);friend Complex operator - (Complex &c1, Complex &c2);friend Complex operator - (Complex &c1, double c2);friend Complex operator - (double c1, Complex &c2);friend Complex operator * (Complex &c1, Complex &c2);friend Complex operator * (Complex &c1, double c2);friend Complex operator * (double c1, Complex &c2);friend Complex operator / (Complex &c1, Complex &c2);friend Complex operator / (Complex &c1, double c2);friend Complex operator / (double c1, Complex &c2);void display ();private:double real;double imag;};Complex operator + (Complex &c1, Complex &c2){Complex c;c.real = c1.real + c2.real;c.imag = c1.imag + c2.imag;return c;} Complex operator + (Complex &c1,double c2){return Complex (c1.real+c2, c1.imag);} Complex operator + (double c1, Complex &c2){return Complex (c1 + c2.real , c2.imag );} Complex operator - (Complex &c1, Complex &c2){return Complex (c1.real + c2.real , c1.imag + c2.imag );}Complex operator - (Complex &c1, double c2){return Complex (c1.real - c2, c1.imag);}Complex operator - (double c1, Complex &c2){return Complex (c1 - c2.real, c2.imag );}Complex operator * (Complex &c1, Complex &c2)//（a+bi）·（c+di）=（ac－bd）+（bc+ad）i{Complex c;c.real = c1.real * c2.real - c1.imag * c2.imag ;c.imag = c1.imag * c2.real - c1.real * c2.imag ;return c;}Complex operator * (double c1, Complex &c2)//（a+bi）·（c+di）=（ac－bd）+（bc+ad）i，{return Complex (c1 * c2.real , c2.imag * c1);}Complex operator * (Complex &c1, double c2)//（a+bi）·（c+di）=（ac－bd）+（bc+ad）i，{return Complex (c1.real * c2, c1.imag * c2);}Complex operator / (Complex &c1,Complex &c2)//（a+bi）÷(c+di)=(ac+bd)/(c^2+d^2) +((bc-ad)/(c^2+d^2))i{Complex c;c.real = (c1.real * c2.real + c1.imag * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);c.imag = (c1.imag * c2.real - c1.real * c2.imag) / (c2.real * c2.real + c2.imag * c2.imag);return c;}Complex operator / (Complex &c1, double c2)//（a+bi）÷(c+di)=(ac+bd)/(c^2+d^2) +((bc-ad)/(c^2+d^2))i{return Complex((c1.real * c2) / (c2 * c2), (c1.imag * c2) / (c2 * c2));}Complex operator / (double c1, Complex &c2)//（a+bi）÷(c+di)=(ac+bd)/(c^2+d^2) +((bc-ad)/(c^2+d^2))i{return Complex ((c1 * c2.real ) / (c2.real * c2.real + c2.imag * c2.imag ), (-c1 * c2.imag ) / (c2.real * c2.real + c2.imag * c2.imag ));}void Complex::display ( )   {cout <<"(" <<real <<"," <<imag <<"i)" <<endl;}

主函数Complex.cpp

#include <iostream>#include "Complex.h"using namespace std;int main(){Complex c1(3, 4), c2(5, -10), c3;cout <<"c1=";c1.display ();cout <<"c2=";c2.display ();c3 = c1 + c2;cout <<"c1+c2=";c3.display ();c3 = c1 + 10;cout <<"c1 + 10=";c3.display ();c3 = 10 + c2;cout <<"10 + c2=";c3.display ();c3 = c1 - c2;cout<<"c1-c2=";c3.display ();c3 = c1 - 10;cout <<"c1 - 10=";c3.display ();c3 = 10 - c2;cout <<"10 - c2=";c3.display ();c3=c1 * c2;cout <<"c1*c2=";c3.display ();c3 = c1 * 10;cout <<"c1 * 10=";c3.display ();c3 = 10 * c2;cout <<"10 * c2=";c3.display ();c3 = c1 / c2;cout <<"c1/c2=";c3.display ();c3 = c1 / 10;cout <<"c1 / 10=";c3.display ();c3 = 10 / c2;cout <<"10 / c2=";c3.display ();system ("pause");return 0;}

开始在函数中

Complex operator + (Complex &c1,double &c2)如此定义c2,后发现不行