第九周 任务三

/* (程序头部注释开始) 
* 程序的版权和版本声明部分 
* Copyright (c) 2011, 烟台大学计算机学院学生  
* All rights reserved. 
* 文件名称：   Triangle.cpp                            
* 作    者：      计114-4   刘向一            
* 完成日期：   2012 年 4月17日 
* 版 本 号：   V 1.0 
* 对任务及求解方法的描述部分 
* 输入描述： 
* 问题描述：
* 程序输出：  
* 程序头部的注释结束 

*/

#include <iostream>  using namespace std; int gcd(int m, int n);      class CFraction    {    private:        int nume;  // 分子        int deno;  // 分母    public:        //构造函数及运算符重载的函数声明        CFraction(int nu=0,int de=1);   //构造函数，初始化用          void Simplify();                //化简（使分子分母没有公因子）            void output();                  //输出：以8/6为例，style为0时，输出8/6；          bool operator > (CFraction &t);          bool operator < (CFraction &t);          bool operator >= (CFraction &t);          bool operator <= (CFraction &t);          bool operator == (CFraction &t);          bool operator != (CFraction &t);          CFraction operator+(CFraction &c);           CFraction operator-(CFraction &c);        CFraction operator*(CFraction &c);          CFraction operator/(CFraction &c);        CFraction operator-();        friend ostream &operator << (ostream &,CFraction &);      friend istream &operator >> (istream &,CFraction &);};istream &operator >> (istream &input,CFraction &c)  {       input>>c.nume>>c.deno;      return input;  }ostream &operator << (ostream &output,CFraction &c)  {      output<<c.nume<<'/'<<c.deno<<endl;       return output;  }CFraction::CFraction(int nu,int de)   //构造函数，初始化用       {    if (de!=0)      {      nume=nu;      deno=de;      }      else      {      cerr<<"初始化中发生错误，程序退出\n";          exit(0);      }      }    void CFraction::Simplify()         //化简（使分子分母没有公因子）     {         int n;        if(nume<0)          {              n=gcd(-nume,deno);          }          else          {              n=gcd(nume,deno);          }nume=nume/n;            deno=deno/n;    }    // 求m，n的最大公约数      int gcd(int m, int n)      {int r;          if (m<n){r=m;m=n;n=r;}          while(r=m%n)                 // 求m，n的最大公约数          {              m=n;              n=r;          }          return n;      }      bool CFraction::operator > (CFraction &t)    {        CFraction c2,c3;        c2.nume=nume*t.deno ;        c3.nume=t.nume*deno;        if(c2.nume>c3.nume )            return true;        else            return false;    }bool CFraction::operator < (CFraction &t)     {        CFraction c2,c3;        c2.nume=nume*t.deno ;        c3.nume=t.nume*deno;        if(c2.nume<c3.nume )            return true;        else            return false;    }bool CFraction::operator >= (CFraction &t)    {          CFraction c1;          c1.nume=nume;        c1.deno=deno;        if (c1<t)              return false;          return true;      }      bool CFraction::operator <= (CFraction &t)    {          CFraction c1;          c1.nume=nume;        c1.deno=deno;        if(c1>t)              return false;          return true;      }      bool CFraction::operator == (CFraction &t)     {        CFraction c1;          c1.nume=nume;        c1.deno=deno;        if (c1<t)              return false;          if (c1>t)              return false;          return false;    }    bool CFraction::operator != (CFraction &t)    {        CFraction c1;          c1.nume=nume;        c1.deno=deno;        if (c1==t)              return false;        return true;    }CFraction CFraction::operator+(CFraction &c)    {        CFraction c2,c3,c4;        c2.nume=nume*c.deno ;        c3.nume=c.nume *deno;        c2.deno=deno*c.deno ;        c3.deno=c.deno *deno;        c4.nume=c2.nume +c3.nume ;        c4.deno=c2.deno ;        c4.Simplify ();        return c4;    }CFraction CFraction::operator-(CFraction &c)    {        CFraction c2,c3,c4;        c2.nume=nume*c.deno ;        c3.nume=c.nume*deno;        c2.deno=deno*c.deno ;        c3.deno=c.deno*deno;        c4.nume=c2.nume-c3.nume ;        c4.deno=c2.deno ;        c4.Simplify ();        return c4;    }CFraction CFraction::operator*(CFraction &c)     {        CFraction c2,c3,c4;        c2.nume=nume*c.nume  ;        c2.deno=deno*c.deno ;        c2.Simplify();        return c2;    }CFraction CFraction::operator/(CFraction &c)    {        CFraction c2,c3;        c2.nume=c.deno ;        c2.deno=c.nume ;        c3.nume=nume*c2.nume ;        c3.deno=deno*c2.deno ;        c3.Simplify ();        return c3;    }CFraction CFraction::operator-()    {        CFraction c2;        c2.nume=nume;        c2.deno=deno;        c2.Simplify ();        if(c2.nume<0 || c2.deno<0)        {            if(c2.nume <0)            {                c2.nume=-nume;            }            else            {                c2.deno=-deno;            }        }        else        {            c2.nume=-nume;            c2.deno=deno;        }        return c2;    }    //用于测试的main()函数    void main()      {          CFraction c1,c2,c;      cout<<"请您输入一个分数c1：（以a b的形式输入）";      cin>>c1;      cout<<"请您输入一个分数c1：（以a b的形式输入）";      cin>>c2;      cout<<"c1为：";          cout<<c1;          cout<<"c2为：";          cout<<c2;          cout<<"下面比较两个时间大小：\n";          if (c1>c2) cout<<"c1>c2"<<endl;          if (c1<c2) cout<<"c1<c2"<<endl;          if (c1==c2) cout<<"c1＝c2"<<endl;           if (c1!=c2) cout<<"c1≠c2"<<endl;          if (c1>=c2) cout<<"c1≥c2"<<endl;          if (c1<=c2) cout<<"c1≤c2"<<endl;          cout<<endl;          cout<<"c1+c2的数值为：";          c=c1+c2;          cout<<c;        cout<<endl;        cout<<"c1-c2的数值为：";          c=c1-c2;          cout<<c;          cout<<endl;          cout<<"c1*c2的数值为：";          c=c1*c2;          cout<<c;        cout<<endl;        cout<<"c1/c2的数值为：";          c=c1/c2;          cout<<c;         cout<<endl;        cout<<"对c1取反的结果为：";        c=-c1;        cout<<c;        cout<<endl;       }