10300 Ecological Premium

Problem A

Ecological Premium

Input: standard input

Output: standard output

Time Limit: 1 second

Memory Limit: 32 MB

German farmers are given a premium depending onthe conditions at their farmyard. Imagine the following simplified regulation:you know the size of each farmer's farmyard in square meters and the number ofanimals living at it. We won't make a difference between different animals,although this is far from reality. Moreover you have information about thedegree the farmer uses environment-friendly equipment and practices, expressedin a single integer greater than zero. The amount of money a farmer receivescan be calculated from these parameters as follows. First you need the space asingle animal occupies at an average. This value (in square meters) is thenmultiplied by the parameter that stands for the farmer'senvironment-friendliness, resulting in the premium a farmer is paid per animalhe owns. To compute the final premium of a farmer just multiply this premiumper animal with the number of animals the farmer owns.

Input

Thefirst line of input contains a single positive integer n (<20), the number of test cases. Each test case starts with aline containing a single integerf(0<f<20), the number of farmers in the test case. This line isfollowed by one line per farmer containing three positive integers each: thesize of the farmyard in square meters, the number of animals he owns and theinteger value that expresses the farmer’s environment-friendliness. Input isterminated by end of file. No integer in the input is greater than100000 or less than 0.

 

Output

Foreach test case output one line containing a single integer that holds thesummed burden for Germany's budget, which will always be a whole number. Do notoutput any blank lines.

 

Sample Input

3

5

1 1 1

2 2 2

3 3 3

2 3 4

8 9 2

3

9 1 8

6 12 1

8 1 1

3

10 30 40

9 8 5

100 1000 70

SampleOutput

38

86

7445

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(The Joint Effort Contest, Problem setter: Frank Hutter)

 

题意：第一行输入一个测试用例的数量（假设m），第二行输入农夫测试用例的数量（假设n），接着是n行数据的输入，每行3个数据，第一个数据是农夫拥有的土地面积，第二个数据是农夫拥有的动物的数量，第三个是生态系数。计算公式是 土地面积/动物数量 × 生态系数 ×动物数量

AC代码如下：

#include <stdio.h>int main(void){int m, n;int a, b, c, sum;int i, j;while (scanf("%d", &m) != EOF) {for (i=0; i<m; ++i) {scanf("%d", &n);sum = 0;for (j=0; j<n; ++j) {scanf("%d%d%d", &a, &b, &c);sum += a * c;}printf("%d\n", sum);}}return 0;}