C/C++算法实例(五)--高精度计算

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高精度数的定义:
type
hp=array[1..maxlen] of integer;

1
.高精度加法

procedure plus ( a,b:hp; var c:hp);
var i,len:integer;
begin
fillchar(c,sizeof(c),0);
if a[0]>b[0] then len:=a[0] else len:=b[0];
for i:=1 to len do begin
inc(c[i],a[i]+b[i]);
if c[i]>10 then begin dec(c[i],10); inc(c[i+1]); end; {
进位}
end;
if c[len+1]>0 then inc(len);
c[0]:=len;
end;{plus}

2
.高精度减法

procedure substract(a,b:hp;var c:hp);
var i,len:integer;
begin
fillchar(c,sizeof(c),0);
if a[0]>b[0] then len:=a[0] else len:=b[0];
for i:=1 to len do begin
inc(c[i],a[i]-b[i]);
if c[i]<0 then begin inc(c[i],10);dec(c[i+1]); end;
while (len>1) and (c[len]=0) do dec(len);
c[0]:=len;
end;

3
.高精度乘以低精度

procedure multiply(a:hp;b:longint;var c:hp);
var i,len:integer;
begin
fillchar(c,sizeof(c),0);
len:=a[0];
for i:=1 to len do begin
inc(c[i],a[i]*b);
inc(c[i+1],(a[i]*b) div 10);
c[i]:=c[i] mod 10;
end;
inc(len);
while (c[len]>=10) do begin {
处理最高位的进位
}
c[len+1]:=c[len] div 10;
c[len]:=c[len] mod 10;
inc(len);
end;
while (len>1) and (c[len]=0) do dec(len); {
若不需进位则调整
len}
c[0]:=len;
end;{multiply}

4
.高精度乘以高精度


procedure high_multiply(a,b:hp; var c:hp}
var i,j,len:integer;
begin
fillchar(c,sizeof(c),0);
for i:=1 to a[0] do
for j:=1 to b[0] do begin
inc(c[i+j-1],a[i]*b[j]);
inc(c[i+j],c[i+j-1] div 10);
c[i+j-1]:=c[i+j-1] mod 10;
end;
len:=a[0]+b[0]+1;
while (len>1) and (c[len]=0) do dec(len);
c[0]:=len;
end;

5
.高精度除以低精度

procedure devide(a:hp;b:longint; var c:hp; var d:longint);
{c:=a div b; d:= a mod b}
var i,len:integer;
begin
fillchar(c,sizeof(c),0);
len:=a[0]; d:=0;
for i:=len downto 1 do begin
d:=d*10+a[i];
c[i]:=d div b;
d:=d mod b;
end;
while (len>1) and (c[len]=0) then dec(len);
c[0]:=len;
end;

6
.高精度除以高精度

procedure high_devide(a,b:hp; var c,d:hp);
var
i,len:integer;
begin
fillchar(c,sizeof(c),0);
fillchar(d,sizeof(d),0);
len:=a[0];d[0]:=1;
for i:=len downto 1 do begin
multiply(d,10,d);
d[1]:=a[i];
while(compare(d,b)>=0) do {
d>=b}
begin
Subtract(d,b,d);
inc(c[i]);
end;
end;
while(len>1)and(c.s[len]=0) do dec(len);
c.len:=len;
end;


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