poj 2608 soundx

//注意重复的或者其soundx值相等的字符应该先去掉！ #include <iostream>#include <string>#include <map>using namespace std;map<char, int> m;int main(){    m['B'] = 1, m['F'] = 1, m['P'] = 1, m['V'] = 1;    m['C'] = 2, m['G'] = 2, m['J'] = 2, m['K'] = 2, m['Q'] = 2, m['S'] = 2, m['X'] = 2, m['Z'] = 2;    m['D'] = 3, m['T'] = 3;    m['L'] = 4;    m['M'] = 5, m['N'] = 5;    m['R'] = 6;    string str1, str2, ans;    int len, i;    while (cin >> str1){          len = str1.length();          str2.clear();          ans.clear();          //将重复的字符进行删除           for (i = 0; i < len; i++){              str2.push_back(str1[i]);              while ((str1[i] == str1[i+1]) || (m[str1[i]] == m[str1[i+1]])) i++;          }          len = str2.length();          for (i = 0; i < len; i++){              if (str2[i] == 'A' || str2[i] == 'E' || str2[i] == 'I' || str2[i] == 'O' || str2[i] == 'U' || str2[i] == 'H' || str2[i] == 'W' || str2[i] == 'Y')                  continue;              else                  ans.push_back(m[str2[i]]+48);           }          cout << ans << endl;    }        system("pause");}