<poj 1056>IMMEDIATE DECODABILITY

IMMEDIATE DECODABILITY

Time Limit: 1000MS Memory Limit: 10000KTotal Submissions: 8811 Accepted: 4177

Description

An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that no two codes within a set of codes are the same, that each code has at least one bit and no more than ten bits, and that each set has at least two codes and no more than eight. 

Examples: Assume an alphabet that has symbols {A, B, C, D} 

The following code is immediately decodable: 
A:01 B:10 C:0010 D:0000 

but this one is not: 
A:01 B:10 C:010 D:0000 (Note that A is a prefix of C) 

Input

Write a program that accepts as input a series of groups of records from standard input. Each record in a group contains a collection of zeroes and ones representing a binary code for a different symbol. Each group is followed by a single separator record containing a single 9; the separator records are not part of the group. Each group is independent of other groups; the codes in one group are not related to codes in any other group (that is, each group is to be processed independently).

Output

For each group, your program should determine whether the codes in that group are immediately decodable, and should print a single output line giving the group number and stating whether the group is, or is not, immediately decodable.

Sample Input

0110001000009011001000009

Sample Output

Set 1 is immediately decodableSet 2 is not immediately decodable 

Source

Pacific Northwest 1998

这题运用string类可以很轻松的解决。

程序中注意两点：sort（i，j），是将下标范围为[i,j)的元素排序。求子串string：：substr（i，j）中，i是所求子串的起始点，j是所求子串的长度。

AC Code:

#include <iostream>#include <algorithm>#include <string>using namespace std;int main(){    string str[8],s;    int set=1,i=-1;    bool flag;    while(cin>>s)    {        if(s!="9")        {            i++;            str[i]=s;        }        else        {            flag=true;            sort(str,str+i+1);//排序            for(int j=0;j<=i-1 && flag;j++)            {                for(int k=j+1;k<=i && flag;k++)                {                    if(str[j]==str[k].substr(0,str[j].length()))                    {                        cout<<"Set "<<set<<" is not immediately decodable"<<endl;                        flag=false;                    }                }            }            if(flag) cout<<"Set "<<set<<" is immediately decodable"<<endl;            set++;            i=-1;        }    }    return 0;}