usaco Money Systems

来源：互联网发布：c 利用java公钥加密编辑：程序博客网时间：2024/04/30 20:15
简单dp
code
/*    ID:yueqi    LANG:C++    TASK:money*/#include <set>#include <map>#include <ctime>#include <queue>#include <cmath>#include <stack>#include <limits.h>#include <vector>#include <bitset>#include <string>#include <cstdio>#include <cstring>#include <fstream>#include <string.h>#include <iostream>#include <algorithm>#define Si set<int>#define LL long long#define pb push_back#define PS printf(" ")#define Vi vector<int>#define LN printf("\n")#define lson l,m,rt << 1#define rson m+1,r,rt<<1|1#define SD(a) scanf("%d",&a)#define PD(a) printf("%d",a)#define SET(a,b) memset(a,b,sizeof(a))#define FF(i,a) for(int i(0);i<(a);i++)#define FD(i,a) for(int i(a);i>=(1);i--)#define FOR(i,a,b) for(int i(a);i<=(b);i++)#define FOD(i,a,b) for(int i(a);i>=(b);i--)#define readf freopen("money.in","r",stdin)#define writef freopen("money.out","w",stdout)const int maxn = 10005;const long long BigP=999983;const long long  INF = 0x5fffffff;const int dx[]={0,1,0,-1};const int dy[]={1,0,-1,0};const double pi = acos(-1.0);const double eps= 1e-7;using namespace std;int N,V,a[26];LL dp[10001];int main(){    readf;    writef;    dp[0]=1;    SD(V);SD(N);    FOR(i,1,V) SD(a[i]);    FOR(i,1,V) FOR(j,a[i],N){        dp[j]+=dp[j-a[i]];    }    printf("%lld\n",dp[N]);    return 0;}