HDU 2057

16进制转换，区别(%X,%x)，另外注意%x,不能输入输出 负数，要另作处理

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A+1A 121A -9-1A -121A -AA

 

Sample Output

02C11-2C-90

#include<cstdio>#include<cstring>#include<algorithm>using namespace std;int main(){    __int64 n,m;    while(scanf("%I64x%I64x",&n,&m)!=EOF)    {        if(n+m<0)        printf("-");        printf("%I64X\n",n+m>0?n+m:-(n+m));    }    return 0;}