一天一个算法题-简单的-递归-N的阶乘

数学公式:result = N!;

设置结束条件相关：n=1

java code

package com.jue.recursion;public class TestRecursion2 {/** * @param args */public static void main(String[] args) {// TODO Auto-generated method stubint n = 5;System.out.println(factorial(n));}public static int factorial(int n) {if (n == 1) {return 1;}return n * factorial(n - 1);}}