打印前20个平凡数（某公司校园招聘笔试题目）

humble数的定义：humber = pow(2, a1) * pow(3, a2) * pow(5, a3) * pow(7, a4); 其中 a1, a2, a3, a4均为非负整数，且不全为0; 打印前20个平凡数的程序为：

 

#include<iostream>using namespace std;bool isHumbleNumber(int number){while(number % 2 == 0)number /= 2;while(number % 3 == 0)number /= 3;while(number % 5 == 0)number /= 5;while(number % 7 == 0)number /= 7;if(number == 1)return true;return false;}void print(){int i = 2, total = 0;while(total <= 20){if(isHumbleNumber(i)){cout << i << " ";total++;}i++;}}int main(){print();cout << endl;return 0;}

程序结果：

2 3 4 5 6 7 8 9 10 12 14 15 16 18 20 21 24 25 27 28 30