二维数组指针

来源:互联网 发布:淘宝违规保证金能退吗 编辑:程序博客网 时间:2024/06/03 04:43

#include <iostream>#include <stdio.h>using namespace std;int main(){        int v[2][10] = {{1,2,3,4,5,6,7,8,9,10},{11,12,13,14,15,16,17,18,19,20}};        int (*a)[10] = v;        cout << "v = " << v << endl;        cout << "*v = " << *v << endl;        cout << "**v+1 = " << **v+1 << endl;        cout << "**(v+1) = " << **(v+1) << endl;        cout << "a = " << a << endl;        cout <<"*a = " << *a << endl;        cout << "**a = " << **a << endl;        cout << "**a+9 = " << **a+9 << endl;        cout << "**a+10 = " << **a+10 << endl;        cout << "**(a+1) = " << **(a+1) <<endl;        cout << "**(a+1)+1 = " << **(a+1)+1 << endl;        cout << "*a[0] = " << *a[0] << endl;        cout << "*a[0]+9 = " << *a[0]+9 << endl;        cout << "*a[0]+10 = " << *a[0]+10 << endl;        cout << "*a[1] = " << *a[1] << endl;        return 0;}运行结果:v = 0x7ffff6b51e00*v = 0x7ffff6b51e00**v+1 = 2**(v+1) = 11a = 0x7ffff6b51e00*a = 0x7ffff6b51e00**a = 1**a+9 = 10**a+10 = 11**(a+1) = 11**(a+1)+1 = 12*a[0] = 1*a[0]+9 = 10*a[0]+10 = 11*a[1] = 11v在这里代表的是v[0]即数组v[2][10]的第一行的首地址,可以说v指向的是一个10维的数组,所以v+1跨过的是10*4.