球队对手排序问题(java面向对象代码解)

package wzs.arithmetics;import java.util.ArrayList;import java.util.List;//题目：两个乒乓球队进行比赛，各出三人。甲队为a,b,c三人，乙队为x,y,z三人。//已抽签决定比赛名单。有人向队员打听比赛的名单。a说他不和x比，c说他不和x,z比，请编程序找出三队赛手的名单。  public class Test_wzs17{    public static void main(String[] args)    {        // 甲队成员排序,固定        Pingpang team1Member = new Pingpang("a", "b", "c");        System.out.println("甲队:" + team1Member);        // 乙队成员        String[] team2Member =        {                "x", "y", "z"        };        // 乙队所有的排序可能        List<Pingpang> team2List = new ArrayList<Pingpang>();        // 乙队临时排序        Pingpang tempTemp;        for (int i = 0; i < 3; i++)        {            for (int j = 0; j < 3; j++)            {                for (int k = 0; k < 3; k++)                {                    tempTemp = new Pingpang(team2Member[i], team2Member[j], team2Member[k]);                    // 球队队员不重复                    if (!tempTemp.member1.equals(tempTemp.member2) && !tempTemp.member2.equals(tempTemp.member3))                    {                        // a说他不和x比，c说他不和x,z比                        if (!tempTemp.member1.equals("x") && !tempTemp.member3.equals("x") && !tempTemp.member3.equals("z"))                        {                            // System.out.println("乙队:" + tempTemp);                            team2List.add(tempTemp);                        }                    }                }            }        }        for (Pingpang pingpang : team2List)        {            System.out.println("乙球:" + pingpang);        }    }}/** * 乒乓球队 * @author wWX154783 *  */class Pingpang{    String member1;// 成员1    String member2;// 成员2    String member3;// 成员3    public Pingpang()    {    }    public Pingpang(String member1, String member2, String member3)    {        this.member1 = member1;        this.member2 = member2;        this.member3 = member3;    }    @Override    public String toString()    {        return "球队成员{" + member1 + "," + member2 + "," + member3 + "}";    }}