走迷宫

/* 
* 程序的版权和版本声明部分: 
* Copyright (c) 2012, 烟台大学计算机学院 
* All rights reserved. 
* 文件名称：【数组】迷宫.cpp 
* 作    者：毛通 
* 完成日期：2012 年 12月 03日 
* 版 本 号：v1.0  

*/

 

#include<iostream>#include<conio.h>using namespace std;void draw(void);             //函数声明    void up(void);void down(void);void left(void);void right(void);void change(void);int map[10][20]=                                          {{1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},{1,2,0,0,1,0,0,0,0,0,1,0,0,0,0,0,1,0,0,1},{1,0,1,0,1,1,0,0,0,1,0,1,0,0,0,0,0,0,0,1},{1,0,0,0,0,0,0,1,1,0,0,0,1,0,1,1,0,1,0,1},{1,0,1,1,0,1,0,0,0,1,0,0,0,0,0,1,1,0,0,1},{1,0,0,1,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,1},{1,0,1,0,1,1,0,0,0,1,0,0,1,0,0,1,0,0,0,1},{1,0,0,1,0,1,0,0,0,0,0,1,0,1,0,1,0,0,0,1},{1,0,0,0,0,1,0,0,1,0,0,1,0,0,0,0,0,0,3,1},    {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1},};                                                //数组初始化的模式int x=1,y=1;             //x y的值需要改变 定义全局变量  int x1=0,y1=0;            //x1 y1的值需要改变 定义全局变量bool victory=false;      //bool变量 开始时为假 用来结束int main(){   draw();                //先画原图    char (ch);while(!victory)     //victory为假时 执行{char (ch);      //字符变量    ch=getch();      //得到字符    switch (ch){case 'w': up();    change();system("cls");draw();break;      case 'a': left();  change();system("cls");draw();break;case 's': down();  change();system("cls");draw();break;case 'd': right(); change();system("cls");draw();break;}}cout<<"恭喜你 你赢啦！"<<endl;return 0;}void  up()                  //改变数组行列{ if(1!=map[x-1][y]){x1=x;y1=y;x=x-1;}}void down(){if(1!=map[x+1][y]){x1=x;y1=y;x=x+1;}}void right(){if(1!=map[x][y+1]){x1=x;y1=y;y=y+1;}}void left(){if(1!=map[x][y-1]){x1=x;y1=y;    y=y-1;}}void  draw()                                      //画迷宫{for (int val = 0; val < 10; ++val)         //行{for (int flag = 0; flag < 20; ++flag)  //列{if (1 == map[val][flag])          //1 为墙{cout << "# ";}else    if (0 == map[val][flag])        //0 为 路{    cout << "  ";}else if (2 == map[val][flag])         //2 为 人{cout << '\001'<<" ";}else if (3==map[val][flag])        //3 为 心cout<<'\003'<<" ";}cout << endl;                         //勿忘换行}}void change()                            //改变迷宫的初始值  （error c2601 自定义函数不能在其他函数里面 通常因为上面的函数大括号没正确匹配）{if (3 == map[x][y])                  //如果吃到心，则胜利{victory = true;}map[x][y] = 2;                      // 原来的路为人map[x1][y1] = 0;                    // 原来的人为路} 

/*
运行结果：

心得体会：   简单数组解决
知识点总结：
*/