关于UI_USER_INTERFACE_IDIOM() & UIDevice.model

来源：互联网发布：信捷plc用什么编程软件编辑：程序博客网时间：2024/06/06 19:28

使用 UI_USER_INTERFACE_IDIOM() 进行区分 (ios 3.2 >=) 无法区分iphone和ipod

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {

// <define your constants here>

} else {

// <define your constants here>

}

区分目前UI_USER_INTERFACE_IDIOM()有2个返回值

UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad

UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone

使用 UIDevice.model 进行区分 (ios 2.0 >=)

NSString *deviceType = [UIDevice currentDevice].model;

if([deviceType isEqualToString:@"iPhone"]) {

//iPhone

}

else if([deviceType isEqualToString:@"iPod touch"]) {

//iPod Touch

}

else {

//iPad

}

使用系统的一个函数sysctlbyname 来获取设备名称

- (NSString *) platformString

{

size_t size;

sysctlbyname("hw.machine", NULL, &size, NULL, 0);

char *machine = malloc(size);

sysctlbyname("hw.machine", machine, &size, NULL, 0);

NSString *platform = [NSString stringWithUTF8String:machine];

free(machine);

if ([platform isEqualToString:@"iPhone1,1"]) return @"iPhone 1G";

if ([platform isEqualToString:@"iPhone1,2"]) return @"iPhone 3G";

if ([platform isEqualToString:@"iPhone2,1"]) return @"iPhone 3GS";

if ([platform isEqualToString:@"iPhone3,1"]) return @"iPhone 4";

if ([platform isEqualToString:@"iPhone3,3"]) return @"Verizon iPhone 4";

if ([platform isEqualToString:@"iPod1,1"]) return @"iPod Touch 1G";

if ([platform isEqualToString:@"iPod2,1"]) return @"iPod Touch 2G";

if ([platform isEqualToString:@"iPod3,1"]) return @"iPod Touch 3G";

if ([platform isEqualToString:@"iPod4,1"]) return @"iPod Touch 4G";

if ([platform isEqualToString:@"iPad1,1"]) return @"iPad";

if ([platform isEqualToString:@"iPad2,1"]) return @"iPad 2 (WiFi)";

if ([platform isEqualToString:@"iPad2,2"]) return @"iPad 2 (GSM)";

if ([platform isEqualToString:@"iPad2,3"]) return @"iPad 2 (CDMA)";

if ([platform isEqualToString:@"i386"]) return @"Simulator";

return @"";

}

原文地址：http://blog.sina.com.cn/s/blog_890a737301014fim.html