不用库函数,用C语言实现将一整型数字转化为字符串

#include<iostream>using namespace std;int getlen(char *s){    int n;    for(n = 0; *s != '\0'; s++)    n++;    return n;}void reverse(char s[]){    char c,i,j;    for(i = 0,j = getlen(s) - 1; i < j; i++,j--)    {        c = s[i];        s[i] = s[j];        s[j] = c;    }}void my_itoa(int n,char s[]){    int i=0,sign;    if((sign = n) < 0)    n = -n;    do    {/*以反序生成数字*/        s[i++] = n%10 + '0';/*get next number*/    }while((n /= 10) > 0);/*delete the number*/    if(sign < 0)    s[i++] = '-';    s[i] = '\0';    reverse(s);}void itochar(int num){    int i = 0;    int j ;    char stra[10];    char strb[10];    while ( num )    {        stra[i++]=num%10+48;        num=num/10;    }    stra[i] = '\0';    for( j=0; j < i; j++)    {        strb[j] = stra[i-j-1];    }    strb[j] = '\0';    cout<<strb<<endl;}int main(){    int num;    cout<<"please input your number"<<endl;    cin>>num;    cout<<"your input is "<<num<<endl;    char b[16]={0};    my_itoa(num,b);    cout<<"after my_itoa(num,b);"<<b<<endl<<endl;    itochar(num);}