LA3708:Graveyard
来源:互联网 发布:java 替换换行符 编辑:程序博客网 时间:2024/05/01 15:07
地址:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=20&page=show_problem&problem=1709
这道题是看了大白书才写得出的,不得不说这思路真是碉堡了!
#include <stdio.h>#include <math.h>int main(){ int n,m; while(~scanf("%d%d",&n,&m)) { int i; double t,ans = 0; for(i = 1;i<=n;i++) { t = (double)i/n*(n+m);//计算需要移动的雕塑的坐标 ans+=fabs(t-floor(t+0.5))/(n+m);//累计移动距离 } printf("%.4lf\n",ans*10000); } return 0;}
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