Java IO读写大文件的几种方式及测试

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读取文件大小:1.45G
第一种,OldIO:
Java代码 复制代码收藏代码
  1. public staticvoid oldIOReadFile() throws IOException{
  2. BufferedReader br = new BufferedReader(new FileReader("G://lily_947.txt"));
  3. PrintWriter pw = new PrintWriter("G://oldIO.tmp");
  4. char[] c = newchar[100*1024*1024];
  5. for(;;){
  6. if(br.read(c)!=-1){
  7. pw.print(c);
  8. }else{
  9. break;
  10. }
  11. }
  12. pw.close();
  13. br.close();
  14. }

耗时70.79s


第二种,newIO:
Java代码 复制代码收藏代码
  1. public staticvoid newIOReadFile() throws IOException{
  2. FileChannel read = new RandomAccessFile("G://lily_947.txt","r").getChannel();
  3. FileChannel writer = new RandomAccessFile("G://newIO.tmp","rw").getChannel();
  4. ByteBuffer bb = ByteBuffer.allocate(200*1024*1024);
  5. while(read.read(bb)!=-1){
  6. bb.flip();
  7. writer.write(bb);
  8. bb.clear();
  9. }
  10. read.close();
  11. writer.close();
  12. }

耗时47.24s


第三种,RandomAccessFile:
Java代码 复制代码收藏代码
  1. public staticvoid randomReadFile() throws IOException{
  2. RandomAccessFile read = new RandomAccessFile("G://lily_947.txt","r");
  3. RandomAccessFile writer = new RandomAccessFile("G://random.tmp","rw");
  4. byte[] b = newbyte[200*1024*1024];
  5. while(read.read(b)!=-1){
  6. writer.write(b);
  7. }
  8. writer.close();
  9. read.close();
  10. }

耗时46.65

第四种,MappedByteBuffer:
Java代码 复制代码收藏代码
  1. public staticvoid mappedBuffer() throws IOException{
  2. FileChannel read = new FileInputStream("G://lily_947.txt").getChannel();
  3. FileChannel writer = new RandomAccessFile("G://buffer.tmp","rw").getChannel();
  4. long i = 0;
  5. long size = read.size()/30;
  6. ByteBuffer bb,cc = null;
  7. while(i<read.size()&&(read.size()-i)>size){
  8. bb = read.map(FileChannel.MapMode.READ_ONLY, i, size);
  9. cc = writer.map(FileChannel.MapMode.READ_WRITE, i, size);
  10. cc.put(bb);
  11. i+=size;
  12. bb.clear();
  13. cc.clear();
  14. }
  15. bb = read.map(FileChannel.MapMode.READ_ONLY, i, read.size()-i);
  16. cc.put(bb);
  17. bb.clear();
  18. cc.clear();
  19. read.close();
  20. writer.close();
  21. }

耗时:36

前三种读法对应的资源占用图如下:
相对于最后一种内存直接映射方式前面的测试其实无意义,基本秒杀。。。。。
对于很大的文件直接分块映射时内存会不够,这是因为MappedByteBuffer未被释放造成的,sun未提供直接回收MappedByteBuffer区域的方法,这个时候有两种方法解决,第一种比较愚笨的:
Java代码 复制代码收藏代码
  1. System.gc();
  2. System.runFinalization();
  3. try {
  4. Thread.sleep(3000);
  5. } catch (InterruptedException e) {
  6. e.printStackTrace();
  7. }

第二种网上找来的,利用反射调用clean方法:
Java代码 复制代码收藏代码
  1. public staticvoid unmap(final MappedByteBuffer buffer) {
  2. if (buffer == null) {
  3. return;
  4. }
  5. AccessController.doPrivileged(new PrivilegedAction<Object>() {
  6. public Object run() {
  7. try {
  8. Method getCleanerMethod = buffer.getClass().getMethod("cleaner",new Class[0]);
  9. if (getCleanerMethod != null) {
  10. getCleanerMethod.setAccessible(true);
  11. Object cleaner = getCleanerMethod.invoke(buffer, new Object[0]);
  12. Method cleanMethod = cleaner.getClass().getMethod("clean",new Class[0]);
  13. if (cleanMethod != null) {
  14. cleanMethod.invoke(cleaner, new Object[0]);
  15. }
  16. }
  17. } catch (Exception e) {
  18. e.printStackTrace();
  19. }
  20. return null;
  21. }
  22. });
  23. }

以上两种方法感觉都别扭,还有就是可以自己分割成物理文件再循环调用,这个也不太美观。
速度也会减慢好多。
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