hdu 1228 A + B

A + B

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10243 Accepted Submission(s): 5867

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =three four + five six =zero seven + eight nine =zero + zero =

Sample Output

39096

Source

浙大计算机研究生复试上机考试-2005年

Recommend

JGShining

直接模拟就不说了。

#include <stdio.h>#include<string.h>int main(){    char num[10][10]={"zero","one","two","three","four","five","six","seven","eight","nine"};    char s[10];    int sum=0,i,a;    while(~scanf("%s",s))    {        if(s[0]=='+')        {            a=sum;            sum=0;            continue;        }        if(s[0]=='=')        {            if(sum==0&&a==0)                break;            printf("%d\n",sum+a);            sum=0;            continue;        }        for(i=0;i<10;i++)        {            if(strcmp(num[i],s)==0)            {                sum*=10;                sum+=i;                break;            }        }    }    return 0;}