hdu 2509 sg博弈

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http://acm.hdu.edu.cn/showproblem.php?pid=2509

题意:从n堆苹果中任意一堆中 取出任意多个连续的个数.最后取光者为输。Fra先下,问是否可以获胜。

和上面那题是一样的。具体详细解法看前面那篇文章。

View Code
// I'm lanjiangzhou//C#include <stdio.h>#include <stdlib.h>#include <string.h>#include <ctype.h>#include <math.h>#include <time.h>//C++#include <iostream>#include <algorithm>#include <cstdio>#include <cstdlib>#include <cmath>#include <cstring>#include <cctype>#include <stack>#include <string>#include <list>#include <queue>#include <map>#include <vector>#include <deque>#include <set>using namespace std;//*************************OUTPUT*************************#ifdef WIN32#define INT64 "%I64d"#define UINT64 "%I64u"#else#define INT64 "%lld"#define UINT64 "%llu"#endif//**************************CONSTANT***********************#define INF 0x3f3f3f3f// aply for the memory of the stack//#pragma comment (linker, "/STACK:1024000000,1024000000")//endconst int maxn  = 110;int a[maxn];int main(){    int n;    while(scanf("%d",&n)!=EOF){        int t=0;        int flag=0;        memset(a,0,sizeof(a));        for(int i=0;i<n;i++){            scanf("%d",&a[i]);            t=t^a[i];            if(a[i]>1){                flag++;            }        }        if(t==0){            if(flag) printf("No\n");            else printf("Yes\n");        }        else if(t){            if(flag) printf("Yes\n");            else printf("No\n");        }    }    return 0;}

 

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