UVaOJ10006 - Carmichael Numbers

10006 - Carmichael Numbers

Time limit: 3.000 seconds

An important topic nowadays in computer science is cryptography. Some people even think that cryptography is the only important field in computer science, and that life would not matter at all without cryptography.  Alvaro is one of such persons, and is designing a set of cryptographic procedures for cooking paella. Some of the cryptographic algorithms he is implementing make use of big prime numbers. However, checking if a big number is prime is not so easy. An exhaustive approach can require the division of the number by all the prime numbers smaller or equal than its square root. For big numbers, the amount of time and storage needed for such operations would certainly ruin the paella.

However, some probabilistic tests exist that offer high confidence at low cost. One of them is the Fermat test.

Let a be a random number between 2 and n - 1 (being n the number whose primality we are testing). Then, nis probably prime if the following equation holds: 

If a number passes the Fermat test several times then it is prime with a high probability.

Unfortunately, there are bad news. Some numbers that are not prime still pass the Fermat test with every number smaller than themselves. These numbers are called Carmichael numbers.

In this problem you are asked to write a program to test if a given number is a Carmichael number. Hopefully, the teams that fulfill the task will one day be able to taste a delicious portion of encrypted paella. As a side note, we need to mention that, according to Alvaro, the main advantage of encrypted paella over conventional paella is that nobody but you knows what you are eating.

Input

The input will consist of a series of lines, each containing a small positive number n ( 2 < n < 65000). A number n = 0 will mark the end of the input, and must not be processed.

Output

For each number in the input, you have to print if it is a Carmichael number or not, as shown in the sample output.

Sample Input

17291756111094310

Sample Output

The number 1729 is a Carmichael number.17 is normal.The number 561 is a Carmichael number.1109 is normal.431 is normal.

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Miguel Revilla 
2000-08-21

题目大意：

            判断一个数是否满足： 1 、 是合数    2、对于任意的2 <= a <= n - 1 是否满足

 

解题方法：

     筛选法得素数表

     (ab) mod c = ((a mod c) * (b mod c)) mod c.    利用这个性质，二分法快速幂取模。

源代码：

#include <cstdio>#include <cstring>#include <cstring>#include <cmath>const int MAXN = 65010;bool prime[MAXN];void init() {    memset(prime, true, sizeof(prime));    for (int i = 2; i <= (int)sqrt(MAXN*1.0); ++i)        if (prime[i])            for (int j = i * i; j < MAXN; j += i)                prime[j] = false;}long long int powmod(int a, int n, int m) {    if (n == 1)        return a % m;    long long int res;    res = powmod(a, n >> 1, m);    res = (res * res) % m;    if (n % 2)        return (a * res) % m;    else        return res;}bool judge(int n) {    if (prime[n])        return false;    for (int i = 2; i < n; ++i)        if (powmod(i, n, n) != i)            return false;    return true;}int main() {    int n;    init();    while (scanf("%d", &n) && n) {        if (judge(n))            printf("The number %d is a Carmichael number.\n", n);        else            printf("%d is normal.\n", n);    }    return 0;}