130716ACM-ICPC World Finals, 2012练习赛Curvy Little Bottles
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#include<iostream>#include<cmath>#include<cstring>#include<string>#include<algorithm>#include<iomanip>#include<cstdio>using namespace std;double pi=acos(-1.0);double getV(double a[],int n,double xl,double xh)//积分算体积,利用for循环写出原函数。{ int i; double ans=0.0,num,sum,tmp; for(i=0; i<=n; ++i) { num=pow(xh,i+1); sum=pow(xl,i+1); tmp=i+1.0; ans+=a[i]*(num-sum)/tmp; //cout<<ans<<endl; } return pi*ans;}double getH(double a[],int n,double xl,double xm,double xh,double V)//二分求答案{ double id=(xh+xm)/2.0; if(abs(V-getV(a,n,xl,id))>0.001) { if((getV(a,n,xl,id)-V)>0) { return getH(a,n,xl,xm,id,V); } else { return getH(a,n,xl,id,xh,V); } } else { return id; }}int main(){ int i,j,k,cas=0,n; double t[30],num[30],low,high,tmp,flag; while(scanf("%d",&n)!=EOF) { cas++; for(i=0; i<=n; ++i) { scanf("%lf",&num[i]); } scanf("%lf%lf%lf",&low,&high,&tmp); memset(t,0.0,sizeof(t));//初始化 for(i=0; i<=n; ++i) { for(j=0; j<=n; ++j) { t[i+j]+=num[i]*num[j]; } } flag=getV(t,2*n,low,high); printf("Case %d: %.2lf\n",cas,flag); if(flag<tmp) { printf("insufficient volume\n");//没有办法分出一个 } else { flag=low; for(i=0; i<8; ++i) { if(getV(t,2*n,low,high)<tmp) { break; } low=getH(t,2*n,low,low,high,tmp); if(i==0)//注意输出空格格式 { printf("%.2lf",low-flag); } else { printf(" %.2lf",low-flag); } } printf("\n"); } } return 0;}
做final的题实在是太受罪了,太难了,最后也只做出这一题。
题意很简单,就是给你个x的多项式,然后此多项式围绕x轴旋转一周形成一个瓶子,先问你瓶子的总体积V,再问每一定体积的x0的间隔。我只能说最简单的题都难成这样,后面咋做啊。。。主要还是太水啊。。。数学题,积分求体积,二分查找。
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