hdu 1018 数学公式

/*公式：log10(n!)=1.0/2*log10(2*pi*n)+n*log10(n/e)*/#include <iostream>#include <cmath>using namespace std;#define PI 3.1415927#define E 2.71828182int main(){int t;double n;cin >> t;while( t-- ){cin >> n;n = 0.5 * log10( 2 * PI * n ) + n * log10( n / E );cout << (int)n + 1 << endl;}}