两种方法实现10进制和62进制互转

来源：互联网发布：被淘宝卖家骂了怎么办编辑：程序博客网时间：2024/05/22 12:59

import java.util.Stack;public class Test {private static char[] charSet = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz".toCharArray();  /** * 将10进制转化为62进制  * @param number  * @param length 转化成的62进制长度，不足length长度的话高位补0，否则不改变什么 * @return */public static String _10_to_62(long number, int length){         Long rest=number;         Stack<Character> stack=new Stack<Character>();         StringBuilder result=new StringBuilder(0);         while(rest!=0){             stack.add(charSet[new Long((rest-(rest/62)*62)).intValue()]);             rest=rest/62;         }         for(;!stack.isEmpty();){             result.append(stack.pop());         }         int result_length = result.length();         StringBuilder temp0 = new StringBuilder();         for(int i = 0; i < length - result_length; i++){         temp0.append('0');         }                  return temp0.toString() + result.toString();}/** * 将62进制转换成10进制数 *  * @param ident62 * @return */private static String convertBase62ToDecimal( String ident62 ) {int decimal = 0;int base = 62;int keisu = 0;int cnt = 0;byte ident[] = ident62.getBytes();for ( int i = ident.length - 1; i >= 0; i-- ) {int num = 0;if ( ident[i] > 48 && ident[i] <= 57 ) {num = ident[i] - 48;}else if ( ident[i] >= 65 && ident[i] <= 90 ) {num = ident[i] - 65 + 10;}else if ( ident[i] >= 97 && ident[i] <= 122 ) {num = ident[i] - 97 + 10 + 26;}keisu = (int) java.lang.Math.pow( (double) base, (double) cnt );decimal += num * keisu;cnt++;}return String.format( "%08d", decimal );}/** * @param args */public static void main(String[] args) {// TODO Auto-generated method stubSystem.out.println("62System=" +_10_to_62(Integer.parseInt("35174605"), 5));System.out.println("10System=" +convertBase62ToDecimal("2NaWL"));}}

运行结果：

62System=2NaWL
10System=35174605

两种方法均转化成功