PAT Basic 1002

来源:互联网 发布:wampserver使用mysql 编辑:程序博客网 时间:2024/05/17 06:12
#include<stdio.h>char a[10][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};/*递归的从左至右输出各个位*/void b(int sum,int count){count++;if(sum/10 !=0 )b(sum/10,count);if(count==1)printf("%s",a[sum%10]);elseprintf("%s ",a[sum%10]);}int main(){char n[102];int i=0,sum=0,r=1;scanf("%s",n);while(n[i]!='\0')sum += n[i++]-48 ;b(sum,0);return 0;}

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