MongoDB 与 SQL 的语法对应关系

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MongoDB 与 SQL 的语法对应关系

SQL Statement Mongo 

Query Language Statement


CREATE TABLE USERS (a Number, b Number)

db.createCollection("mycoll", {capped:true, size:100000})


INSERT INTO USERS VALUES(1,1) 

db.users.insert({a:1,b:1})


SELECT a,b FROM users 

db.users.find({}, {a:1,b:1})


SELECT * FROM users 

db.users.find()

SELECT * FROM users WHERE age=33 

db.users.find({age:33})


SELECT a,b FROM users WHERE age=33 

db.users.find({age:33}, {a:1,b:1})


SELECT * FROM users WHERE age=33 ORDER BY name 

db.users.find({age:33}).sort({name:1})


SELECT * FROM users WHERE age>33 

db.users.find({'age':{$gt:33}})})


SELECT * FROM users WHERE age<33 

db.users.find({'age':{$lt:33}})})


SELECT * FROM users WHERE name LIKE "%Joe%" 

db.users.find({name:/Joe/})


SELECT * FROM users WHERE name LIKE "Joe%" 

db.users.find({name:/^Joe/})


SELECT * FROM users WHERE age>33 AND age<=40 

db.users.find({'age':{$gt:33,$lte:40}})})


SELECT * FROM users ORDER BY name DESC 

db.users.find().sort({name:-1})


CREATE INDEX myindexname ON users(name) 

db.users.ensureIndex({name:1})


CREATE INDEX myindexname ON users(name,ts DESC) 

db.users.ensureIndex({name:1,ts:-1})


SELECT * FROM users WHERE a=1 and b='q' 

db.users.find({a:1,b:'q'})


SELECT * FROM users LIMIT 10 SKIP 20 

db.users.find().limit(10).skip(20)


SELECT * FROM users WHERE a=1 or b=2 

db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } )


SELECT * FROM users LIMIT 1 

db.users.findOne()


EXPLAIN SELECT * FROM users WHERE z=3 

db.users.find({z:3}).explain()


SELECT DISTINCT last_name FROM users 

db.users.distinct('last_name')


SELECT COUNT(*y) FROM users 

db.users.count()


SELECT COUNT(*y) FROM users where AGE > 30 

db.users.find({age: {'$gt': 30}}).count()


SELECT COUNT(AGE) from users 

db.users.find({age: {'$exists':true}}).count()


UPDATE users SET a=1 WHERE b='q' 

db.users.update({b:'q'}, {$set:{a:1}}, false, true)


UPDATE users SET a=a+2 WHERE b='q' 

db.users.update({b:'q'}, {$inc:{a:2}}, false, true)


DELETE FROM users WHERE z="abc" 

db.users.remove({z:'abc'});