MINESWEEPER题解

来源：互联网发布：js判断edge浏览器内核编辑：程序博客网时间：2024/04/28 21:17

这题也比较简单，只要先把参数从文件读出来，然后做一组判断即可，这题没有看第二遍的价值。

#include <iostream>#include <fstream>#include <string>using namespace std;string convertStr(string str, int m, int n) {int num;for(int i=0; i<m; i++) {for(int j=0; j<n; j++) {num = 0;if(str[i*n+j] == '*') continue;if(i>=1) {if(str[(i-1)*n+j] == '*') ++num;if(j>=1)if(str[(i-1)*n+j-1] == '*') ++num;if(j<n-1)if(str[(i-1)*n+j+1] == '*') ++num;}if(i<m-1) {if(str[(i+1)*n+j] == '*') ++num;if(j<n-1)if(str[(i+1)*n+j+1] == '*') ++num;if(j>=1)if(str[(i+1)*n+j-1] == '*') ++num;}if(j>=1) {if(str[i*n+j-1] == '*') ++num;}if(j<n-1){if(str[i*n+j+1] == '*') ++num;}str[i*n+j] = num+'0';}}return str;}int main (int argc, char* argv[]) {ifstream file;string lineBuffer;file.open(argv[1]);while (!file.eof()) {getline(file, lineBuffer);if (lineBuffer.length() == 0)continue; //ignore all empty lineselse {string str1, str2;int M, N;int start = lineBuffer.find_first_of(";");str1 = lineBuffer.substr(0, start);str2 = lineBuffer.substr(start+1);sscanf(str1.c_str(), "%d,%d", &M, &N);cout << convertStr(str2, M, N) << endl;}}return 0;}

0 0