如何反转一个单链表 How to reverse a singly linked list
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用3个指针 分别指向前面 ,正在 ,下一个3个state,
class Node //节点类
...{
int data;
Node * link;
}
Node * Reverse(const Node * head)//反转 非递归算法
...{
Node * pre,*cru,* next;
pre=head;
cru=head->link;
while(cru!=null)
...{
next=cru->link;
cru->link=pre;
pre=cru;
cru=next;
}
...{
int data;
Node * link;
}
Node * Reverse(const Node * head)//反转 非递归算法
...{
Node * pre,*cru,* next;
pre=head;
cru=head->link;
while(cru!=null)
...{
next=cru->link;
cru->link=pre;
pre=cru;
cru=next;
}
head->link=null;
head=pre;
return headl
}
}
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