LeetCode OJ:Add Two Numbers

来源:互联网 发布:linux shellcode 编辑:程序博客网 时间:2024/06/08 18:55

Add Two Numbers

 

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8


/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public:    ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {        ListNode *p=l1,*q=l2,*r;        ListNode *nh=new ListNode(0);        r=nh;        int c=0,s;        while(p||q){            s=c;            if(p)s+=p->val;            if(q)s+=q->val;            r->next=new ListNode(s%10);            c=s/10;            r=r->next;            if(p)p=p->next;            if(q)q=q->next;        }        if(c)r->next=new ListNode(c);        return nh->next;    }};


0 0
原创粉丝点击